magnification of concave mirror

It only takes a minute to sign up. for lenses, both being on the same side means they have different properties. Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. for mirrors, both being on the same side of the mirror means they have the same property. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. the image is enlarged i.e. this use of sign is analogous to signs on vectors to indicate direction on an axis. 10th Physics | Light | Linear Magnification Produced by Mirrors. People who already know really well how to solve this problem know what to do with the solution, but the notation and the negative signs and absolute values are likely different from the notation in your textbook and in class if I had to guess... this is the first solution on the following topic and i know this topic very well but i am really getting confused on this following solution i think i am not able to link something in the solution. Why does a spoon form a virtual image though it is a concave mirror? Concave mirror is a curved surface with reflection covering external piece of the curve. $4=-v/x$, (We know that $m=4$ and $u=-x$ here $u=x$ because this is formula is already sign covensed so no need to change $x$ to $-x$) As the concave lens the image will be always virtual and erect if magnification is positive. Thanks for contributing an answer to Physics Stack Exchange! To subscribe to this RSS feed, copy and paste this URL into your RSS reader. And the magnification formula is $\frac{-v}{u}=m$, so why does the solution include the modulus of the formula? Notify me of follow-up comments by email. It is denoted by the letter ‘m’ and is given by. since u is assigned a negative value $-x$, then $v$ must also be a negative value if the image is real (now the information is given to you). Mathematically it is defined as. A convex mirror always forms a virtual and erect image. object and image: if both are real, both must have the same sign. in concave lens magnification cannot be negative because if it is negative the image should be inverted and real as in the convex lens but it is not true in concave lens. In the question it is given that the object size is magnified 4 times, and not the distance of the of the object from the mirror. the image is of the same size as the object. The solution in my textbook has the following data stated: $u=-x$ as it is assumed that the object is real. The image is diminished i.e. (ii) For virtual and Erect image : According to the new Cartesian sign convention, for the virtual and erect images formed by a concave mirror. Can we omit "with" in the expression glow with (something)? Great example of how to answer homework question: help in understanding without feeding the solution. Object distance is the distance of the object from the pole of the mirror; denoted by the letter u. i know all that i am good at this topic but i am getting confused on the following assumption's made in text-book $ v=−4x$ as it is assumed in case 1 that a real image will be formed and $|\frac{v}{u}|=|m|=4$. $-4x=v$. concave mirrors have positive $f$ and convex mirrors have negative $f$. $v=-4x$, it came form $m=-\frac{v}{u}$, Your email address will not be published. Required fields are marked *, You may use these HTML tags and attributes:

. How can I change a math symbol's size globally? Does PostgreSQL always sequentially scan pages in the same order? Two PhD programs simultaneously in different countries. rev 2020.11.24.38066, The best answers are voted up and rise to the top, Physics Stack Exchange works best with JavaScript enabled, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site, Learn more about Stack Overflow the company, Learn more about hiring developers or posting ads with us. Your email address will not be published. $u$ is the distance of the object to the reflecting/refracting surface. Magnification of a concave mirror can be defined as negative of the ratio of the distance of the image distance to the object distance which is also equal to negative of the ratio of the size of image to the size of object . the image is smaller than the object. $u=-x$ ,here $x$ is the value of object distance, as per sign convention $x$ becomes $-x$ because $x$ is being left of the mirror. $4x=-v$, then comes Asking for help, clarification, or responding to other answers. By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. The expression which gives t… The linear magnification ‘m’ is also related to the object distance (u) and image distance (v). greater than the object. It is a pure ratio and has no units. for magnification, positive values indicate that the image is the same orientation as the object (object upright, image also upright), negative if the image is inverted relative to the object. in fact it is implicit from the rules above that for concave mirrors, real images are always inverted--an upright image must be a virtual image.

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